| [Responses to Comments] |
| (C1) |
Problem 13-a - the signs of the lattice energy in the task and in the solution are opposite? |
| (Re1) |
The example of the solution for the problem 13a is correct.
The definition of the lattice energy is "the energy required to separate completely the ions of a crystal to an infinite distance". Thus, the sign of the lattice energy is a plus. (31 March 2010) |
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| (C2) |
Solution 20-a - the stoichiometric coefficient by the oxide is 2m/n? |
| (Re2) |
See (A5) in [Corrections] above. (Revised 10 May 2010) |
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| (C3) |
Would you happen to know where we can buy the modified silica TLC plates that are used in problem 35? |
| (Re3) |
See the pdf file Suppl_info_problem_35.pdf. (8 Aptil 2010) |
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| (C4) |
There is a mistake in problem 9 (e)?
The answer 9e is:
Calculate the energy width from the lowest occupied level to the highest occupied level.
I think that lowest occupied is wrong and the correct word is lowest unoccupied or LUMO.
This is also consistent with point (f) of the same problem. |
| (Re4) |
The gaps between discrete energy levels become narrower as the number of atoms
increases in a one-dimensional quantum well model.
The descrete levels are treated as a broad band, when a sufficient number of atoms are involved.
The intention of problem 9(e) is to have the energy width of the occupied band, the
energy difference between the lowest occupied level and the highest occupied level.
The description "the lowest occupied level" is good enough for Problem 9(e).
Could you please confirm the meaning from the solution? (8 Aptil 2010) |
| (C5) |
Problem 8 (f).
Question (f) should define atoms that looks like argon.
Personally I find Chlorine would be a better fit.
Don't you think there may be a mistake in your solution? |
| (Re5) |
Please see the "Correction to Preparatory Problem 8" in the Errata section. (30 April 2010) |
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| (C6) |
We did not completely understand the details of the official
solution of problem 21a.
A little more detail would be welcomed. |
| (Re6) |
Please see the Supplementary to Solution for Problem 21. (10 May 2010) |
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